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UNIT 3 · 4–7%

Composite, Implicit & Inverse

chain rule saves lives (and exam points) 🔗

🔗 chain rule

d/dx [f(g(x))] = f′(g(x)) · g′(x)

In Leibniz notation: if y = f(u) and u = g(x), then dy/dx = dy/du · du/dx.

For nested chains, multiply derivatives layer by layer (like peeling an onion 🧅).

🌙 implicit differentiation

Use when x and y are mixed and solving for y is annoying. Differentiate both sides with respect to x, remembering d/dx[y] = y′ (or dy/dx) and chain rule on yTerms.

Example: x² + y² = r² ⇒ 2x + 2y y′ = 0 ⇒ y′ = −x/y

↩️ inverse functions

(f⁻¹)′(a) = 1 / f′(f⁻¹(a))   (when denominators behave)

For inverse trig, memorize the shapes (constants over square roots).

📐 inverse trig derivatives

  • d/dx [arcsin x] = 1 / √(1 − x²)
  • d/dx [arccos x] = −1 / √(1 − x²)
  • d/dx [arctan x] = 1 / (1 + x²)

Don't forget chain rule multipliers when the inside isn't just x.

📈 higher-order derivatives

f″, f‴, f⁽⁴⁾… each is the derivative of the previous. Notation: d²y/dx² for second derivative.

Acceleration in motion: if s(t) is position, v = s′, a = s″.

✏️ quick practice

  1. Find d/dx [sin(3x² + 1)].
  2. Find y′ if x³ + xy + y³ = 7 (implicit).
  3. Compute d/dx [arctan(5x)].

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